All of the 48 students in the fifth grade class at Parker Elementary School voted for the favorite of their two teachers. Of the 25 girls in the fifth grade, 11 voted for Mr. Ackerman. Of the 23 boys in the fifth grade, 7 voted for Ms. Husted.

Given:
Total number of student in fifth grade class = 48
Among 25 girls,
Mr. Ackerman got = 11 votes
Among 23 boys,
Mr. Husted got = 7 votes.
To find the given answers.
Now,
Number of girls who voted for Mr. Husted = (25-11) = 14
Number of boys who voted for Mr. Ackerman = (23-7) = 16
Completing the table we get,
                    Boys         Girls       Total
Mr. Ackerman         16           11          27
Mr. Husted            7            14          21
Total                 23           25          48
Again,
The percentage of girls in fifth grade who voted for Mr. Husted is = [tex]\frac{14}{25} (100)%[/tex] % = 56%.
Therefore,
a) Mr. Ackerman was voted favorite by the greater number of students of fifth grade class.
b) Mr. Ackerman was voted favorite by the greater number of boysin the fifth grade class.
c) 56% of the girls in fifth grade class voted for Mr. Husted as their favorite teacher.
The answers are provided here. To understand, check calculations.
A). The complete table is provided below.
B). Mr. Ackerman.
C). Mr. Ackerman
D). 56%
A). Table is as follows:
                 Boys voted         Girls voted         Total
Mr. Ackerman         16                  11               27
Mr. Husted            7                    14              21
Total                 23                   25
B). This data itself shows that Mr. Ackerman got maximum votes i.e. 27.
C). The favorite teacher among boys is Mr. Ackerman as the majority voted for him.
D). Percentage of votes from girls received by Mr. Husted:
= 14/25 × 100
[tex]=[/tex] 56%
Thus, the above answer is correct.
Learn more about "Percentage" here:
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