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What is the pressure of 0.540 mol of an ideal gas at 35.5 L and 223 K?
Use P V equals n R T. and R equals 8.314 StartFraction L times kilopascals over moles time K EndFraction..
0.715 kPa
2.45 kPa
28.2 kPa
62.7 kPa

Respuesta :

Answer:

Pressure, P = 28.2 kPa

Explanation:

Given that,

Number of moles, n = 0.54 mol

Volume of ideal gas, V = 35.5 L

Temperature, T = 223 K

We need to find the pressure of ideal gas. The equation of ideal gas is given by :

[tex]PV=nRT[/tex]

R is gas constant

P is pressure

[tex]P=\dfrac{nRT}{V}\\\\P=\dfrac{0.54\ mol\times 8.314\ kPa- L/mol- K\times 223\ K}{35.5\ L}\\\\P=28.2\ kPa[/tex]

So, the pressure of the gas is 28.2 kPa.                              

Answer:

28.2

Explanation:

on edge

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