DummyC
contestada

Find the domain of
[tex]y = \sqrt{x + 6} [/tex]
A. x ≥ -1/6

B. x > 6

C. x ≥ -6

D. x ≥ 6​

Respuesta :

Answer:

C (x ≥ -6)

Step-by-step explanation:

Algebraic:

The domain of [tex]\sqrt{x}[/tex] is [tex]x\geq 0[/tex]. When transformed 6 units to the left, it becomes [tex]x\geq -6[/tex]

Graphically:

As shown in the attached graph, [tex]x\geq -6[/tex] .

Ver imagen jakeob28

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