A rock falls from rest off a cliff and hits the ground in 2 seconds. If there is no air resistance, determine the rock's velocity as the rock hits the ground.

A Rock falling off a cliff can be modeled as an object starting with zero velocity moves with constant acceleration for certain period of time, for such motion following equation of motion can be used.

[tex]v(t) = v_{0} +at[/tex]

here in our case [tex]v_{0} =0[/tex] because object starts off from rest and [tex]a = g =9.8m/s^2[/tex] is acceleration because of gravity ( Motion under gravity).

and of course t = 2 second.

Now by substituting all this information in equation of motion we get.

[tex]v(2s) = 0+9.8m/s^2 *2s = 19.6m/s[/tex]

that would be the velocity of rock as it would hit the ground.

Note! We have assumed that there is no air resistance.

A rock falling off a cliff can be modeled as an object starting with zero velocity moves with constant acceleration for a certain period of time, for such motion following equation of motion can be used.

here in our case because object starts off from rest and is acceleration because of gravity ( Motion under gravity).

and of course t = 2 seconds.

Now by substituting all this information in equation of motion we get.

V = 19.6m/s

that would be the velocity of rock as it would hit the ground.

Note! We have assumed that there is no air resistance.