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Which is the value of this expression when a = 5 and k = negative 2?

(StartFraction 3 squared a Superscript negative 2 Baseline Over 3 a Superscript negative 1 Baseline EndFraction) Superscript k

Respuesta :

From what I see in the problem, the expression is

[tex](\frac{3^a^2}{3a^-1} )^k[/tex]

To solve, plug in a and k.

[tex](\frac{3^(5)^2}{3*5^-1} )^-2[/tex]

3*5^2=75

(3*5)^-1 = 1/15

[tex]75 / \frac{1}{15} = 5[/tex]

5^-2 = 1/25

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