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1/36 chance because there are 36 different possible ways it could land. And you are only looking for 1 kind (4:4)
varshamittal029

Probability of getting two 4's is 1/36

What is required probability ?

Tess rolls 2 fair dice.

The possibilities of first die are 1, 2, 3, 4, 5 or 6.

Also the possibilities of second die are 1, 2, 3, 4, 5 or 6.

So, the number of possibilities is 36, when tess rolls 2 dice together.

Here, possibility of getting two 4's is 1 out of 36

∴ The probability of getting two 4's = 1/36

Learn more about dice problem here :

https://brainly.com/question/12727360

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