Answer:
–0.029 to 0.229.
Step-by-step explanation:
So, we are given the following data or information or values/parameters which are going to help us in solving this particular equation:
=>" A class of entering freshmen = 6000 or more students) respectively"
=> "The class of entering freshmen graduated in the bottom third of their high school class."
=>" 99% confidence interval for p1 – p2"
Let p1 = k1 and p2 = k2
Here, we can deduce that p1 > p2; k1 > k2. Hence,
a = (1 - 0.99)/2 = 0.005.
b = 513 × 0.005 = 2.6.
c = standard deviation = ✓ [ k1 (1 - k1) / j1 + k2 (1 - k2) / j2] = 0.05.
99% confidence interval for p1 – p2 =
k1 - k2 - b × c = –0.029
Also, k1 - k2 + b × c = 0.029.
Which are the lower and upper boundaries respectively.
