Answer:
The answer is "(1, -12)"
Step-by-step explanation:
In the given question some information is missing, that is the attachment of the graph, which can be attached as follows:
In the attached figure file, the quadrilateral ABCD vertices are (-3, 4), (3,4),(1,-2), and (-5,-2)
To find the coordinates of the D' the translation of (x, y) = (x + 6, y-10)
where point D=(-5, -2),
[tex]\to x=x+6\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=y-10\\\\\to x=-5+6 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=-2-10 \\\\\to x=1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \to y=-12[/tex]
So, the coordinates of D' is (1,-12).
