Respuesta :
Answer and Step-by-step explanation: To find the B-coordinate vector of x:
[tex]b_{1} = \left[\begin{array}{ccc}1\\2\\-3\end{array}\right][/tex] , [tex]b_{2} = \left[\begin{array}{ccc}-4\\-7\\11\end{array}\right][/tex], x = [tex]\left[\begin{array}{ccc}-10\\-17\\27\end{array}\right][/tex]
The augmented matrix will be:
[tex]\left[\begin{array}{ccc}1&-4&-10\\2&-7&-17\\-3&11&27\end{array}\right][/tex]
Transforming into reduced row-echelon form:
= [tex]\left[\begin{array}{ccc}1&-4&-10\\0&1&3\\0&-1&-3\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}1&-4&-10\\0&1&3\\0&0&0\end{array}\right][/tex]
= [tex]\left[\begin{array}{ccc}1&0&2\\0&1&3\\0&0&0\end{array}\right][/tex]
The values for the vector will be:
x = 2
y = 3
The B-coordinate vector is of the form:
V = [tex]\left[\begin{array}{ccc}x\\y\end{array}\right][/tex]
V = [tex]\left[\begin{array}{ccc}2\\3\end{array}\right][/tex]
The B-coordinate vector of x is V = [tex]\left[\begin{array}{ccc}2\\3\end{array}\right][/tex]
