Answer:
The time interval is [tex]t = 21.30 \ s[/tex]
Explanation:
From the question we are told that
The constant acceleration is [tex]\alpha = 0.029 \ rad / s^2[/tex]
The displacement is [tex]\theta = 6.58 \ rad[/tex]
According to the second equation of motion we have that
[tex]\theta = w_i* t + \frac{1}{2} * \alpha t^2[/tex]
given that the blade started from rest
[tex]w_i[/tex] which is the initial angular velocity is 0
So
[tex]\theta = 0 + \frac{1}{2} * \alpha t^2[/tex]
=> [tex]t = \sqrt{ \frac{2 * \theta }{\alpha } }[/tex]
substituting values
=> [tex]t = \sqrt{ \frac{2 * 6.58 }{0.029 } }[/tex]
=> [tex]t = 21.30 \ s[/tex]
