The length of a rectangle is shown below: (look at the picture) If the area of the rectangle to be drawn is 12 square units, where should points C and D be located if they lie vertically below the line that connects B and A, to make this rectangle? C(−2, −1), D(1, −1) C(−2, −4), D(1, −4) C(−2, −2), D(1, −2) C(−2, −5), D(1, −5)

The length of a rectangle is shown below look at the picture If the area of the rectangle to be drawn is 12 square units where should points C and D be located class=

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Answers:

C(-2,-2) and D(1,-2)

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Explanation:

The distance from B to A, or vice versa, is 3 units. You can count out the spaces between the points, or you could subtract the x coordinate values then use absolute value

|B - A| = |-2-1| = |-3| = 3

or

|A - B| = |1-(-2)| = |1+2| = |3| = 3

Whichever method you prefer, the distance between the two points is 3 units.

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The area of the rectangle is 12 square units, and we know one dimension of the rectangle is 3 units. The other dimension must be 12/3 = 4 units.

Point C is directly below point B. Specifically C is 4 units below B.

Start at B(-2,2) and move down 4 units to get to C(-2,-2). Then move to the right 3 units to get to D(1,-2)

Or you could start at A(1,2) and move 4 units down to get to D(1,-2) and then move 3 units to the left to get to C(-2,-2)

Answer:

Answer choice = B - C(−2, −4), D(1, −4)