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Sulphur dioxide and oxygen reacts to form sulphur trioxide. The equilibrium mixture contain 5.0 × 10−2 M SO3, 3.0 × 10−3 M SO2 and 3.5 × 10−3 M O2. Calculate equilibrium constant for reaction?

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Answer:

Keq = 79365

Explanation:

Based on the reaction of sulphur dioxide, SO2, with O2, to produce SO3:

2SO2 + O2 ⇄ 2SO3

The equilibrium constant of reaction (Defined as the ratio of concentrations of products over reactants powered to the coefficient of each reactant). For the reaction:

Keq = [SO3]² / [SO2]² [O2]

Replacing with concentrations of the problem:

Keq = [5.0x10⁻²]² / [3.0x10⁻³]² [3.5x10⁻³]

Keq = 79365

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