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In training for a swim meet, Logan swam 750 meters in \large \frac {1}{3}

3

1

​ of an hour. His swimming partner, Mila, swam \frac {2}{3}

3

2

​ of Logan's distance in \frac {1}{4}

4

1

​ of an hour.

Respuesta :

Answer:

v = 0.625 m/s

Step-by-step explanation:

Given that,

Total distance is 750 m

Logan swan 750 m in 1/3 hours

His swimming partner, Mila, swam 2/3 of Logan's distance in 1/4 hours.

Note: We need to find Logan's average swimming speed.

Average speed = total distance/total time taken

[tex]v=\dfrac{750\ m}{\dfrac{1}{3}\times 3600\ s}\\\\v=0.625\ m/s[/tex]

So, Logan's average speed is 0.625 m/s.

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