Given:
The sum of the smallest prime number and the second smallest prime number is divided by the third smallest prime number.
To find:
The remainder.
Solution:
Prime numbers are the numbers which are divided by only 1 or itself.
Smallest prime number = 2
Second smallest prime number = 3
Third smallest prime number = 5
The sum of the smallest prime number and the second smallest prime number is divided by the third smallest prime number.
[tex]\dfrac{2+3}{5}=\dfrac{5}{5}[/tex]
[tex]\dfrac{2+3}{5}=1[/tex]
Since 5 is completely divided by 5, therefore, t he remainder is 0.