What is the remainder when the sum of the smallest prime number and the second smallest prime number is divided by the third smallest prime number

Respuesta :

Given:

The sum of the smallest prime number and the second smallest prime number is divided by the third smallest prime number.

To find:

The remainder.

Solution:

Prime numbers are the numbers which are divided by only 1 or itself.

Smallest prime number = 2

Second smallest prime number = 3

Third smallest prime number = 5

The sum of the smallest prime number and the second smallest prime number is divided by the third smallest prime number.

[tex]\dfrac{2+3}{5}=\dfrac{5}{5}[/tex]

[tex]\dfrac{2+3}{5}=1[/tex]

Since 5 is completely divided by 5, therefore, t he remainder is 0.