Answer:
(-2, -3)
Step-by-step explanation:
If a segment having extreme ends as [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is divided by a point (x, y) in the ratio of m:n,
x = [tex]\frac{mx_2+nx_1}{m+n}[/tex]
y = [tex]\frac{my_2+ny_1}{m+n}[/tex]
Since, a line RT has extreme ends as R(-5, 3) and T(-1, -5) then a point S(x, y) which divides RT in the ratio of 3 : 1 will be,
x = [tex]\frac{3(-1)+1(-5)}{3+1}[/tex]
= [tex]\frac{-8}{4}[/tex]
= -2
y = [tex]\frac{3(-5)+1(3)}{3+1}[/tex]
= [tex]-\frac{12}{4}[/tex]
= -3
Therefore, coordinates of the point S will be (-2, -3).
