Answer: The area of the triangle with the perimeter of 540 cm is approximately 10200 cm²
More exactly: 10182 cm²
Step-by-step explanation: [tex]A=\frac{bh}{2}[/tex]
240 × 84.85 = 10182
To get the height of the triangle, it takes some trigonometry;
Given 3 sides of a triangle, it is possible to calculate the angles using the Law of cosines and the formula [tex]cos A =\frac{b^{2} +c^{2} -a^{2} }{2bc}[/tex]
We will need the measure of angle A, then use the sine of A to get the height of the line from angle C perpendicular to the base, side b.
We can use the dimensions given in the proportions and then multiply by 10 because the sides given add to a perimeter of 54, one tenth of the 540 cm of the actual triangle. The angles of the similar triangles are congruent.
side a = 19, side b = 24, side c = 11
24² + 11² - 19² is 576 + 121 - 361 = 336
2(24)(11) = 528
cos A = 336 / 528 that is 0.636364[tex]\cos^{-1}\left(.6363634\right)[/tex]= 50.47°
sin(50.47) = 0.77129
0.77129 × 11 = 8.48 is the height Rounding to 8.5 would be reasonable for this height
Using rounded values here to calculate Area :
85 × 240/2 = 10200 cm²
