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An object with a initial velocity of 0m/s accelerates at a rate of 4m/s how much time did it take to go 88m?

Respuesta :

machmillerg

Answer:

6.633s

Explanation:

For this equation we use the following kinematic equation:

^D = Vi(t)+(1/2)(a)(t)^2

88m-0m = 0m/s(t)+(0.5)(4m/s^2)(t)^2

88m = 2m/s^2(t^2)

t^2 = 44s

t = sqrt(44)

t = 6.633s

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