Given :
- [tex] \sf f(x) =4x+1[/tex]
- [tex] \sf g(x)=x²-5[/tex]
To Find :
- [tex] \sf (f . g)(x)[/tex]
Solution :
We know that,
[tex] \Large \underline{\boxed{\sf{ (f . g)(x) = f(x) \times g(x) }}}[/tex]
By substituting values :
[tex] \sf : \implies (f . g)(x) = (4x+1) \times (x^{2} -5)[/tex]
[tex] \sf : \implies (f . g)(x) = 4x(x^{2} -5) +1(x^{2} -5)[/tex]
[tex] \sf : \implies (f . g)(x) = 4x^{3} - 20x + x^{2} -5[/tex]
[tex] \sf : \implies (f . g)(x) = 4x^{3} + x^{2} - 20x -5[/tex]
Hence, answer is :
[tex]\underline{\boxed{\sf{(f . g)(x) = 4x^{3} + x^{2} - 20x - 5}}}[/tex]
