Answer:
The new height of the water will:
[tex]H_{new}=22.89 cm[/tex]
Step-by-step explanation:
The submerged volume due to an object in a liquid, water in our case, is equal to the displaced volume of the water, it is the Archimedes principle.
The volume of a golf ball (sphere) will be
[tex]V_{ball}=\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi 2.2^{3}[/tex]
[tex]V_{ball}=44.6 cm^{3}[/tex]
We have 5 golf balls, so the total volume will be:
[tex]V_{5-ball}=5*44.6 cm^{3}=223\: cm^{3}[/tex]
Using Archimedes' principle the extra volume of water will be 223 cm³
Now, we know that the cylinder has a radius of 3 cm, then the height related to 223 cm³ will be:
[tex]223=\pi r^{2}h[/tex]
[tex]223=\pi 3^{2}h[/tex]
[tex]h=7.89\: cm[/tex]
Therefore, the new height of the water will:
[tex]H_{new}=15+7.89=22.89 cm[/tex]
I hope it helps you!
