Answer:
Step-by-step explanation:
Let the ends of the given segment are A and B.
Coordinates of A → (8, 6)
Coordinates of B → (12, 12)
If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,
(x, y) → (kx, ky)
If k = [tex]\frac{2}{3}[/tex]
(x, y) → [tex](\frac{2}{3}x, \frac{2}{3}y)[/tex]
By this rule coordinates of the image points of A and B will be,
A(8, 6) → [tex]A'(\frac{2\times 8}{3},\frac{2\times 6}{3})[/tex]
→ A'(5.3, 4)
B(12, 12) → [tex]B'(\frac{12\times 2}{3}, \frac{12\times 2}{3})[/tex]
→ B'(8, 8)
Now we can get the image of segment AB after dilation by a scale factor of [tex]\frac{2}{3}[/tex].
