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An arrow is shot at 30.0° above the horizontal. Its velocity is 49 m/s, and it hits the target.
What is the maximum height the arrow will attain?

Respuesta :

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Answer:

30.625 m

Step-by-step explanation:

Maximum Height :

(u²sin²θ) / 2g

u = 49 m/s

θ = 30°

g = 9.8m/s

(49² * 0.5²) / 2 * 9.8

600.25 / 19.6

= 30.625 m

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