Answer:
[tex]\boxed{\textsf{ The slope of the line is $\bf{\dfrac{3}{2}}$.}}[/tex]
Step-by-step explanation:
Two points are given to us and we need to find the slope of the line that passes through these two points . The two points are (3,-2) and (9,-2) .As we know that the slope of the line is given by [tex]\tan\theta[/tex]
Slope of a line is :-
[tex]\qquad\boxed{\boxed{ \sf Slope =\dfrac{ y_2-y_1}{x_2-x_1}=\tan\theta }}[/tex]
On using this formula we can find the slope of the line .
Putting the respective values :-
[tex]\sf\implies Slope = \dfrac{y_2-y_1}{x_2-x_1}\\\\\sf\implies Slope = \dfrac{ 9-3}{2+2} \\\\\sf\implies Slope =\dfrac{6}{4}\\\\\sf\implies\boxed{\pink{\sf Slope = \dfrac{3}{2} }}[/tex]
