Respuesta :
Answer:
1.12 N
Explanation:
Let the masses be m and M and distance be d . Force between them is .28 N .
Applying Newton's law of Gravitation
.28 = G x m M / d²
distance is halved , so distance becomes d /2
Force of attraction = G m M / ( d/2)²
= 4 Gm M / d²
= 4 x .28
= 1.12 N .
The force of attraction be if the distance between these masses is halved is equal to 1.12 N.
Gravitational force
To calculate the gravitational force of attraction it is necessary to use the following relationship:
[tex]F_{g} = G \frac{M \times m}{d^{2}}[/tex]
Thus, with the value given by the question, we have that:
[tex]0.28 N = G \frac{M \times m}{d^{2}}[/tex]
When the distance is divided in half we will have:
[tex]F_{g} = G \frac{M \times m}{(d/2)^{2}}[/tex]
[tex]F_{g} = G \frac{M \times m}{d^{2}/4}[/tex]
[tex]F_{g} = 4\times G \frac{M \times m}{d^{2}}[/tex]
[tex]F_{g} = 4 \times 0.28 = 1.12 N[/tex]
So, the force of attraction be if the distance between these masses is halved is equal to 1.12 N.
Leran more about gravitational force in: brainly.com/question/24783651
