Answer:
[tex]T_2= 31.9\°C[/tex]
Explanation:
Hello there!
In this case, it is possible to propose an energy balance in order to illustrate how the heat released by the reaction is absorbed by the water:
[tex]-Q_{rxn}=Q_{water}[/tex]
Thus, since the heat released by the reaction is -112 kJ (-112000 J), it is possible to define the hear absorbed by the water in terms of mass, specific heat and temperature change:
[tex]-(-112000J)=m_{water}C_{water}(T_2-T_1)[/tex]
In such a way, it is possible to define the final temperature as shown below:
[tex]T_2=23.8\°C+\frac{112000J}{3300g*4.18\frac{J}{g\°C} }\\\\T_2= 31.9\°C[/tex]
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