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Secants ⎯⎯⎯⎯⎯⎯⎯⎯⎯ and ⎯⎯⎯⎯⎯⎯⎯⎯⎯ intersect in the exterior of a circle. ∠ measures 27.42° and the measure of DE is 73.18°. Determine the measure of BC.

Secants and intersect in the exterior of a circle measures 2742 and the measure of DE is 7318 Determine the measure of BC class=

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akposevictor

Answer:

BC = 18.34°

Step-by-step explanation:

Recall: Exterior angle formed by 2 secants = ½(the difference of the measures of the intercepts arcs)

Thus:

m<BAC = ½(DE - BC)

27.42° = ½(73.18 - BC) => Substitution

Multiply both sides by 2

2*27.42 = 73.18 - BC

54.84 = 73.18 - BC

BC = 73.18 - 54.84

BC = 18.34°

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