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A 1 kg object sits on the earth’s surface. What is the force of gravity between the object and the earth? (mass of the earth = 5.97 x 10 24kg, radius of the earth = 6.37 x 10 6m)

Respuesta :

Answer:

9.81N

Explanation:

the force of attraction is given by

F=GmM/

where m is mass of the body

M is mass of the earth

R is radius of the earth

G is the universal gravitational constant(6.67x10-¹¹)

hence we substitute the values in the formula.

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The force of gravity between the object and the earth? (mass of the earth = 5.97 x 10 24kg, radius of the earth = 6.37 x 10 6m) is 9.8 N.

using Newton's law of universal gravitation,

F = G m₁m₂ / r²

where

F = force of gravity

G = 6.67 × 10⁻¹¹N.m² / kg²

m₁ = mass of the object = 1kg

m₂ = mass of the earth = 5.97  ×  10²⁴ kg

r = distance from the centre = 6.37  × 10⁶ m

Therefore,

F = 6.67 × 10⁻¹¹ × 1 × 5.97  ×  10²⁴ / 6.37  × 10⁶

F = 39.8199 × 10¹³ / (6.37  × 10⁶)²

F = 39.8199 × 10¹³ / 4.05  × 10¹³

F = 9.83207407407

F ≈ 9.8 N

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