Answer:
100.87°C
Explanation:
This is about elevation of boiling point, one of the colligative properties.
Formula is:
Boiling T° of solution - Boiling T° of pure solvent = Kb . m . i
Kb is the boiling constant.
m means molality (mol/kg of solvent)
i = numbers of ions dissolved.
Our solute is C₂H₆O₂. As it is an organic compound, no ion is generated, so i = 1.
We determine moles of solute: 125 g . 1mol /62g = 2.02 moles.
We determine molality = 2.02 mol / 1.2 kg → 1.68 m.
Boiling T° of solution - 100°C = 0.52°C/m . 1.68m . 1
Boiling T° of solution = 0.52°C/m . 1.68m . 1 + 100°C → 100.87 °C
