Respuesta :

GilliamKathren

Answer:

I believe the answer is x + 3

Step-by-step explanation:

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Let the width be w

Its length = x + 5

Area of rectangle = x² + 8x + 15

Area of ractangle = Length × Width

w ( x + 5 ) = x² + 8x + 15

w ( x + 5 ) = x² + 5x + 3x + 15 ( Split middle term and factorise )

w ( x + 5 ) = x ( x + 5 ) + 3 ( x + 5 )

w ( x + 5 ) = ( x + 5 ) ( x + 3 )

[tex]{ \large{ \sf{w = \dfrac {\cancel{(x + 5)}(x + 3)}{ \cancel{x + 5}} }}}[/tex]

width = ( x + 3 ) Answer. Option. ( B )

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