Answer:
450000 six digit even numbers are possible if the leftmost digit cannot be zero.
Step-by-step explanation:
We have to find Total six digit even numbers.
To form an even of 6 digit we have 10 digits to place in first 5 position starting from left most, here repetition is allowed so, No ways of doing this is [tex]10^5[/tex] and number of ways selecting one digit from 5 digit for ones place is [/tex]^{5}\textrm{P}_{1}=\farc{5!}{(5-1)!}=\frac{5!}{4!}=5[/tex]
So, Total even numbers = [tex]10^5\times5=500000[/tex]
This includes number which has zero on the left most place.
To get these numbers we fir 0 at place 2 left 4 places has 9 options and ones place has 5 options as before.
So, Number of such cases = [tex]10^4\times5=50000[/tex]
Thus, total Number of 6 Digit number even number = 500000 - 50000 = 450000
Therefore, 450000 six digit even numbers are possible if the leftmost digit cannot be zero.
