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One square is placed inside another square so that their diagonals overlap. If the larger square has a side of 6 and the smaller square has a side of 4, how far is it from the vertex of the larger square to the corresponding vertex in the smaller square (marked in red)?

2–√

22–√

32–√

4?√

One square is placed inside another square so that their diagonals overlap If the larger square has a side of 6 and the smaller square has a side of 4 how far i class=

Respuesta :

[tex]a_1=4,a_2=6 \\d_1=4 \sqrt{2} ,d_2=6 \sqrt{2} \\ \\x= \frac{d_2-d_1}{2}= \frac{6 \sqrt{2} -4 \sqrt{2}}{2} = \frac{2 \sqrt{2} }{2} = \sqrt{2} [/tex]