Answer:
x = 1
Step-by-step explanation:
Given
[tex]\frac{2x^2-7x-4}{x^2-5x+4}[/tex] ← factor numerator and denominator
= [tex]\frac{(x-4)(2x+1)}{(x-4)(x-1)}[/tex] ← cancel (x - 4) on numerator/ denominator
= [tex]\frac{2x+1}{x-1}[/tex]
The denominator of the rational expression cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the value that x cannot be.
x - 1 = 0 ⇒ x = 1 ← excluded value
Answer:
On edge it is D, 1 and 4
Step-by-step explanation:
Why was it impossible to find this answer
