In the diagram below, AB = 15, DB = 6, BC = 8, and
mZB = 90°. What is the perimeter of triangle ADC?

Answer:
B 36
Step-by-step explanation:
DC^2=6^2+8^2. AD=9cm DB=6cm
DC^2=36+64
DC^2=100
DC=√100
DC=10cm
AC^2=15^2+8^2
AC^2=225+64
AC^2=289
AC=√289
AC=17
P OF TRIANGLE ADC=10+9+17
=36cm