contestada

On a coordinate plane, a parabola opens down. It has an x-intercept at (negative 5, 0), a vertex at (negative 1, 16), a y-intercept at (0, 15), and an x-intercept at (3, 0).
The function f(x) = –x2 − 2x + 15 is shown on the graph. What are the domain and range of the function?

The domain is all real numbers. The range is {y|y < 16}.
The domain is all real numbers. The range is {y|y ≤ 16}.
The domain is {x|–5 < x < 3}. The range is {y|y < 16}.
The domain is {x|–5 ≤ x ≤ 3}. The range is {y|y ≤ 16}

Respuesta :

laurendiannephillips

Answer:

the domain is xl-5<×< 3 is the range of 16

oladayoademosu

The domain is all real numbers. The range is {y|y ≤ 16}.

Domain of the function

The domain of a function is all the of values of the input or independent variable into the function

Since the x-intercepts of the function are at (-5, 0) and (3, 0), and also, the graph opens downwards, the values of x are in the interval (-∞ ≤ x ≤ -5) ∪ (-5 ≤ x ≤ 3) ∪ (3 ≤ x ≤ ∞). This is (-∞ ≤ x ≤ ∞).

So, the domain is the set of all real numbers.

The range of a function

The range of a function is all the output values of the function

Since the vertex of the parabola is at (-1, 16) and its y-intercept is at (0, 15), the maximum value of y is 16. So, the values of y are in the range y ≤ 16.

So, the range of the function is {y|y ≤ 16}

So, the domain is all real numbers. The range is {y|y ≤ 16}.

Learn more about domain and range of a function here:

https://brainly.com/question/10197594

Otras preguntas