Reaction of 2,3-dimethyl-1-butene with HBr leads to an alkyl bromide, C6H13Br. On treatment of this alkyl bromide with KOH in methanol, elimination of HBr occurs and a hydrocarbon that is isomeric with the starting alkene is formed. What is the structure of this hydrocarbon, and how do you think it is formed from the alkyl bromide

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22-06-2021
Chemistry

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Reaction of 2,3-dimethyl-1-butene with HBr leads to an alkyl bromide, C6H13Br. On treatment of this alkyl bromide with KOH in methanol, elimination of HBr occurs and a hydrocarbon that is isomeric with the starting alkene is formed. What is the structure of this hydrocarbon, and how do you think it is formed from the alkyl bromide

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pstnonsonjoku pstnonsonjoku · Answer 1 · 2021-06-24T04:58:00+02:00

Answer:

See explanation and image attached

Explanation:

The image attached shows the entire scheme of reactions mentioned in the question.

The first reaction is an addition reaction which yields a tertiary alkyl halide as shown in accordance with Markovnikov rule.

The second reaction is a dehydrohalogenation in which the base abstracts a proton from the alkyl halide followed by loss of a bromide ion to yield the corresponding alkene.

This alkene is an isomer of the starting material.