Answer:
-65
-61
20ab - 3bc - 3ac
Step-by-step explanation:
1.) Find the sum of 72−104+5and -32+ 4-10.
72 - 104 + 5 = - 27
- 32 + 4 - 10 = - 38
Sum of (-27 and - 38) = - 27 + (-38) = - 65
2.) What should be added to 32+32+3 to get 3+3
32 + 32 + 3 = 67
3 + 3 = 6
67 + x = 6
x = 6 - 67
x = - 61
3.) Subtract the sum of 12ab –10bc –18ac and 9ab +12bc + 14ac from the sum of ab + 2bc and 3bc –ac
(12ab –10bc –18ac) + (9ab +12bc + 14ac)
12ab + 9ab - 10bc + 12bc - 18ac + 14ac
= 21ab + 2bc - 4ac
(ab + 2bc) + (3bc - ac)
ab + 2bc + 3bc - ac
ab + 5bc - ac
(21ab + 2bc - 4ac) - (ab + 5bc - ac)
21ab + 2bc - 4ac - ab - 5bc + ac
21ab - ab + 2bc - 5bc - 4ac + ac
20ab - 3bc - 3ac
