Respuesta :
Answer:
1) b. 4.38
2) d. 10.7
Explanation:
1) The problem tells us that [H₃O⁺] = 4.2x10⁻⁵ M, and keeping in mind that [H₃O⁺]= [H⁺], we can calculate the pH of the solution:
- pH = -log[H⁺] = 4.38
2) First we calculate the pOH of the solution:
- pOH = -log[OH⁻] = -log(4.6x10⁻⁴) = 3.33
Then we calculate the pH using the following formula:
- pH = 14 - pOH = 14 - 3.33
- pH = 10.7
The pH of a solution with a concentration of 4.2x10⁻⁵ M H₃O⁺ ion is 4.38 and of a solution with a concentration of 4.6x10⁻⁴ OH⁻ ion is 10.7.
What is pH and pOH?
pH of any solution is define as the negative log of the concentration of H⁺ ions and pOH is define as the negative log of the concentration of OH⁻ ions.
Given that concentration of H⁺ ions in solution = 4.2x10⁻⁵ M
pH for this solution is calculated as:
pH = -log(4.2x10⁻⁵) = 4.38
Also given that concentration of OH⁻ ions in solution = 4.6x10⁻⁴
pOH = -log(4.6x10⁻⁴) = 3.33
We know that, pH + pOH = 14.
pH = 14 - 3.33 = 10.7
Hence, value of pH & pOH is 4.38 and 10.7 respectively.
To know more about pH & pOH, visit the below link:
https://brainly.com/question/24595796