Using scale concepts, it is found that the length of her office is of 10 ft, while the width is of 5 ft.
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First, we find the actual length:
6 cm - 15 ft
4 cm - x ft
[tex]6x = 60[/tex]
[tex]x = \frac{60}{6}[/tex]
[tex]x = 10[/tex]
The actual length is of 10 ft.
Then, we find the actual width:
6 cm - 15 ft
2 cm - x ft
[tex]6x = 30[/tex]
[tex]x = \frac{30}{6}[/tex]
[tex]x = 5[/tex]
The actual width is of 5 ft.
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