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A 130 N horizontal force keeps a 30 kg chair moving at a constant velocity. Find the coefficient of kinetic friction between the chair and the floor.

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Lanuel

The coefficient of kinetic friction between the chair and the floor is 0.44.

Given the following data:

  • Horizontal force = 130 N
  • Mass of chair = 30 kg

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]

To find coefficient of kinetic friction between the chair and the floor:

Mathematically, the coefficient of kinetic friction between two objects is given by the formula;

[tex]u = \frac{F_k}{mg}\\\\u = \frac{130}{30[9.8]}\\\\u = \frac{130}{294}[/tex]

Coefficient of kinetic friction, u = 0.44.

Read more: https://brainly.com/question/13754413

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