After how many minutes will the two pools have the same amount of water? 36 min.
How much water will be in each pool when they have the same amount? 2638 liters.
Explanation:
y=1900+20.5x
y=1351+35.75x
Let the time be t
[tex]\\ \sf\longmapsto 1900(1+\dfrac{20.5}{100})^t=1351(1+\dfrac{35.75}{100})^t[/tex]
[tex]\\ \sf\longmapsto 1900(\dfrac{120.5}{100})^t=1351(\dfrac{135.75}{100})^t[/tex]
[tex]\\ \sf\longmapsto 1900(1.2)^t=1351(1.35)^t[/tex]
[tex]\\ \sf\longmapsto \dfrac{1900}{1351}=\left(\dfrac{1.35}{1.2}\right)^t[/tex]
[tex]\\ \sf\longmapsto 1.4=(1.125)^t[/tex]
[tex]\\ \sf\longmapsto (1.125)^2.9=(1.125)^t[/tex]
[tex]\\ \sf\longmapsto t=2.9h[/tex]
