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Darth21

Answer:

Well we can make an equation

so supplementary angles are 2 or more angles that add up to 180

In this case it’s only two.

We can make the first angle “x”

Whilst the second angle “y”

The measure of the first angle is 40 more then half the second angle so

X is the first angle

we know that x is (y/2)+40

So we can subsitute that in and then we can add y which is the second angle

(y/2) + 40 + y = 180

Now solve

I multiplied everything by 2 to get rid of fractions

y+80+2y= 360

And then combine like terms

3y + 80 = 360

Now isolate 3y

3y= 280

now isolate y to solve

y= 90 1/3

And then we subsitue

((90 1/3 ) / 2 ) + 40= 85 1/6

So you have this

first angle : 85 1/6

Second angle; 90 1/3

charlief22

Answer:

[tex]86\frac{2}{3}[/tex] and [tex]93\frac{1}{3}[/tex]

Step-by-step explanation:

Two angles that are supplementary mean that they both add up to 180°.

If one angle is 40 more than half the second angle then,

a = [tex]\frac{b}{2}[/tex] + 40

Both angles together would be:

180 = [tex]\frac{b}{2} + 40 + b[/tex]

Step 1 - Subtract 40 from both sides of the equation:

[tex]180 - 40 = \frac{b}{2} + 40 + b - 40\\140 = \frac{b}{2} + b[/tex]

Step 2 - Multiply both sides by 2:

[tex]140 \times2 = 2(\frac{b}{2}) + 2(b)\\280 = b + 2b\\280 = 3b[/tex]

Step 3 - Divide both sides by 3:

[tex]\frac{3b}{3} = \frac{280}{3}[/tex]

[tex]b = 93 \frac{1}{3}[/tex]

Step 4 - Plug this into the original equation to calculate the angle:

[tex]\frac{b}{2} + 40\\[/tex]

[tex]\frac{93\frac{1}{3} }{2} + 40\\46\frac{2}{3} + 40 = 86\frac{2}{3}[/tex]

Therefore the two angles are:

[tex]86\frac{2}{3}[/tex] and [tex]93\frac{1}{3}[/tex]

Hope this helps!

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