Variation can be direct, inverse or jointly
Jordan's first error is that he incorrectly calculated the value of proportionality constant
From the question, we understand that f varies directly as the square root of g.
This variation is represented as:
[tex]\mathbf{ f\ \alpha\ \frac{1}{\sqrt{g}}}[/tex]
Express as a equation
[tex]\mathbf{ f\ \ =\ k\frac{1}{\sqrt{g}}}[/tex]
When f = 4, k = 4.
So, we have:
[tex]\mathbf{ 4\ \ =\ k\frac{1}{\sqrt{4}}}[/tex]
[tex]\mathbf{ 4\ \ =\ \frac{k}{2}}[/tex]
Multiply both sides by 2
[tex]\mathbf{ k = 8}[/tex]
When g = 100, we have:
[tex]\mathbf{ f\ \ =\ k\frac{1}{\sqrt{g}}}[/tex]
[tex]\mathbf{ f\ \ =\ 8 \times \frac{1}{\sqrt{100}}}[/tex]
[tex]\mathbf{ f\ \ =\ 8 \times \frac{1}{10}}[/tex]
[tex]\mathbf{ f\ \ = 0.8}[/tex]
This means that, Jordan incorrectly calculated the value of proportionality constant
Read more about variation at:
https://brainly.com/question/1698891
