You are studying a population of geese in which there are two color phases, brown and gray. Color in this species is controlled by a single gene, with brown dominant to gray. A random sample of 250 geese shows that 210 are brown. What percentage of the brown geese are heterozygous

Respuesta :

Based on the information given the percentage of the brown geese that are heterozygous is 48%.

Random sample = 250

Brown color = 210

Gray color = 250 - 210 = 40

First step is to calculate the proportion of a alleles in the population

Proportion (a alleles)=√40/250

Proportion (a alleles)= √0.16

Proportion (a alleles)= 0.4

Second step is to calculate the proportion of A alleles in the population

p(A) = 1 - 0.4

p(A)= 0.6

Third step is to calculate brown heterozygous percentage using this formula

Brown heterozygous percentage=2pq(Aa)

Let plug in the formula

Brown heterozygous percentage= 2 x 0.6 x 0.4

Brown heterozygous percentage= 0.48 ×100

Brown heterozygous percentage= 48%

Inconclusion  the percentage of the brown geese that are heterozygous is 48%.

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