Based on the information given the percentage of the brown geese that are heterozygous is 48%.
Random sample = 250
Brown color = 210
Gray color = 250 - 210 = 40
First step is to calculate the proportion of a alleles in the population
Proportion (a alleles)=√40/250
Proportion (a alleles)= √0.16
Proportion (a alleles)= 0.4
Second step is to calculate the proportion of A alleles in the population
p(A) = 1 - 0.4
p(A)= 0.6
Third step is to calculate brown heterozygous percentage using this formula
Brown heterozygous percentage=2pq(Aa)
Let plug in the formula
Brown heterozygous percentage= 2 x 0.6 x 0.4
Brown heterozygous percentage= 0.48 ×100
Brown heterozygous percentage= 48%
Inconclusion the percentage of the brown geese that are heterozygous is 48%.
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