Answer:
E
Step-by-step explanation:
Using the cosine and sine ratios in the right triangle and the exact values
cos60° = [tex]\frac{1}{2}[/tex] , sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] , then
cos60° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{s}{10}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2s = 10 ( divide both sides by 2 )
s = 5
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sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{q}{10}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )
2q = 10[tex]\sqrt{3}[/tex] ( divide both sides by 2 )
q = 5[tex]\sqrt{3}[/tex]