A 0. 05 C charge is placed in a uniform electric field pointing downward with a strength of 100 Newtons over Coulombs. Determine the magnitude and direction of the force on the charge. 5 N downward 5 N upward 2000 N downward 2000 N upward.

Respuesta :

The magnitude of the force applying on the charge is 5 N and the direction of the force will be the same as the electric field.

What is an electric field?

It is an area in space around a charged particle where other charged particles experience a force either attractive or repulsive.

[tex]F = qE[/tex]

Where,

[tex]q[/tex] - Charge = 0. 05 C

[tex]E[/tex] - electric field  = 100 N/C

Put the values in the formula,

[tex]F = 0.05 \times 100\\\\F = 5 \rm \ N[/tex]

Therefore, the magnitude of the force applying on the charge is 5 N and the direction of the force will be the same as the electric field.

Learn more about the electric field:

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Answer:

5 N Downward

Explanation:

Just did on edge