A number from 0 to 9 is randomly selected and then a letter from A to D is randomly selected. What is the probability that the number 3 and a consonant are selected?

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Answer:

[tex]\frac{1}{10}*\frac{3}{4} =\frac{3}{40}[/tex]

Step-by-step explanation:

There are 10 numbers 0,1,…9

Probability that 3 is selected is  [tex]\frac{1}{10}[/tex]

Again, there are 4 letters A,B,C & D of which 3 are consonants and 1 is vowel. So, probability of selecting a consonant is [tex]\frac{3}{4}[/tex] . Hence, the required probability is [tex]\frac{1}{10} *\frac{3}{4} = \frac{3}{40}[/tex]

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