a. The probability is 1/100 since there are 10 possible digits (0-9) and you need the last two digits so [tex]\frac{1}{10}*\frac{1}{10}=\frac{1}{100}[/tex].
This is 1%.
b. Let's start by calculating the probability of getting the right digits knowing that they are both even.
We have a total of 5 even digits (0, 2, 4, 6, 8). You need the last two so [tex]\frac{1}{5}*\frac{1}{5} =\frac{1}{25}=\frac{4}{100}[/tex] which is 4%.
Therefore the answer is a) It increases the probability that your choice is correct to 1/25, or 4%, because each digit could be 0, 2, 4, 6 or 8.
