Respuesta :
1) The missing properties are [tex]\nu = 0.001093\,\frac{m^{3}}{kg}[/tex], [tex]u = 639.54\,\frac{kJ}{kg}[/tex] and [tex]h = 640.59\,\frac{kJ}{kg}[/tex]. (Subcooled liquid)
2) The missing properties are [tex]T = 263.94\,^{\circ}C[/tex], [tex]\nu = 0.0163\,\frac{m^{3}}{kg}[/tex], [tex]u = 1719\,\frac{kJ}{kg}[/tex] and [tex]x = 0.394[/tex]. (Liquid-gas mix)
3) The missing properties are [tex]T = 422.825\,^{\circ}C[/tex], [tex]\nu =0.0603\,\frac{m^{3}}{kg}[/tex] and [tex]u = 3251.7\,\frac{kJ}{kg}[/tex]. (Superheated steam)
4) The missing properties are [tex]P = 0.36873\,kPa[/tex], [tex]u = -337.836\,\frac{kJ}{kg}[/tex], [tex]h = -337.458\,\frac{kJ}{kg}[/tex] and [tex]x = 2.988\times 10^{-3}[/tex]. (Solid-gas mix)
How to determine the phase of water based on information from steam tables
In this question we must determine the phase associated to the given pressure ([tex]p[/tex]), in kilopascals, temperature ([tex]T[/tex]), in degrees Celsius, specific volume ([tex]\nu[/tex]), in cubic meters per kilogram, internal energy ([tex]u[/tex]), in kilojoules per kilogram, enthalpy ([tex]h[/tex]), in kilojoules per kilogram, or quality ([tex]x[/tex]), no unit.
1) Pressure - 500 kPa, Temperature - 100 °C
By steam tables we know that saturation temperature associated with pressure is 151.83 °C, which means that water is a subcooled liquid and quality does not apply herein.
The missing properties are summarized below:
[tex]\nu = 0.001093\,\frac{m^{3}}{kg}[/tex], [tex]u = 639.54\,\frac{kJ}{kg}[/tex], [tex]h = 640.59\,\frac{kJ}{kg}[/tex]
The missing properties are [tex]\nu = 0.001093\,\frac{m^{3}}{kg}[/tex], [tex]u = 639.54\,\frac{kJ}{kg}[/tex] and [tex]h = 640.59\,\frac{kJ}{kg}[/tex]. (Subcooled liquid) [tex]\blacksquare[/tex]
2) Pressure - 5000 kPa, Specific enthalpy - 1800 kJ/kg
By steam tables we know that water is a mix of gaseous and liquid phases. Hence, the missing properties are summarized below:
[tex]T = 263.94\,^{\circ}C[/tex], [tex]\nu = 0.0163\,\frac{m^{3}}{kg}[/tex], [tex]u = 1719\,\frac{kJ}{kg}[/tex], [tex]x = 0.394[/tex]
The missing properties are [tex]T = 263.94\,^{\circ}C[/tex], [tex]\nu = 0.0163\,\frac{m^{3}}{kg}[/tex], [tex]u = 1719\,\frac{kJ}{kg}[/tex] and [tex]x = 0.394[/tex]. (Liquid-gas mix) [tex]\blacksquare[/tex]
3) Pressure - 5000 kPa, Internal energy - 2950 kJ/kg
By steam tables we know that water is a superheated steam. Hence, missing properties are summarized below:
[tex]T = 422.825\,^{\circ}C[/tex], [tex]\nu =0.0603\,\frac{m^{3}}{kg}[/tex], [tex]u = 3251.7\,\frac{kJ}{kg}[/tex]
The missing properties are [tex]T = 422.825\,^{\circ}C[/tex], [tex]\nu =0.0603\,\frac{m^{3}}{kg}[/tex] and [tex]u = 3251.7\,\frac{kJ}{kg}[/tex]. (Superheated steam) [tex]\blacksquare[/tex]
4) Temperature - -6°C, Specific volume: 1 m3/kg
By ice tables we know that properties correspond to a mix of solid and gaseous phases. Thus, missing properties are summarized below:
[tex]P = 0.36873\,kPa[/tex], [tex]u = -337.836\,\frac{kJ}{kg}[/tex], [tex]h = -337.458\,\frac{kJ}{kg}[/tex], [tex]x = 2.988\times 10^{-3}[/tex]
The missing properties are [tex]P = 0.36873\,kPa[/tex], [tex]u = -337.836\,\frac{kJ}{kg}[/tex], [tex]h = -337.458\,\frac{kJ}{kg}[/tex] and [tex]x = 2.988\times 10^{-3}[/tex]. (Solid-gas mix) [tex]\blacksquare[/tex]
To learn more on water, we kindly invite to check this verified question: https://brainly.com/question/4381433
