Respuesta :
1: Factor the problem
(x^2+5)(x^2-4)=0
2: Set each equal to 0
x^2+5=0
x^2-4=0
3: Solve Each
x^2=-5
- Cannot take square root of a negative, therefore extraneous
x^2=4
x= 2, -2
(x^2+5)(x^2-4)=0
2: Set each equal to 0
x^2+5=0
x^2-4=0
3: Solve Each
x^2=-5
- Cannot take square root of a negative, therefore extraneous
x^2=4
x= 2, -2
Find all the solutions to the given polynomial. x^4+x^2-20=0 x^2+5=0
x^2-4=0, x^2=-5
x^2=4
x= 2, -2
x^2-4=0, x^2=-5
x^2=4
x= 2, -2