Which system of equations can be used to find the roots of the equation 4 x squared = x cubed 2 x? startlayout enlarged left-brace 1st row y = negative 4 x squared 2nd row y = x cubed 2 x endlayout startlayout enlarged left-brace 1st row y = x cubed 4 x squared 2 x 2nd row y = 0 endlayout startlayout enlarged left-brace 1st row y = 4 x squared 2nd row y = negative x cubed minus 2 x endlayout startlayout enlarged left-brace 1st row 4 x squared 2nd row y = x cubed 2 x endlayout

Respuesta :

The system of equations can be used to find the roots of the considered  equation is y = 4+x^2 and y= x^3 + 2 + x

How can we find the solution to an equation?

We do same operations on both the sides so that equality of both expressions doesn't get disturbed. Solving equations generally means finding the values of the variables used in it for which the considered equation is true.

Sometimes we can find such value, and sometimes it is not possible at all, or sometimes, there are infinite number of solutions.

For the given case, we are given with the equation [tex]4+x^2 = x^3 + 2 + x[/tex]

We can take two equations as:

[tex]y = 4+x^2 \\y= x^3 + 2 + x[/tex]

And when we will try to solve this system of equation, we will end up substituting the value of y in terms of x, and therefore, ending up on the same equation [tex]4+x^2 = x^3 + 2 + x[/tex]

Learn more about solving system of equations here:

https://brainly.com/question/2825832

Answer:

D

y=4x^2

y=x^3+2x

Step-by-step explanation:

im trying to pass just like yall, Good luck to all