From the mole ratio of the gases, 10 moles of hydrogen will produce 10 moles of water, and if 10.0 L of hydrogen and 6.0 L of oxygen were used, 10.0 L of water will be produced.
The mole ratio of the reactants in the formation of water can be shown from the equation below:
[tex]2H_2 + O_2 \rightarrow 2H_2O[/tex]
Mole ratio of hydrogen to oxygen is 2:1
10 moles of hydrogen will require 5 moles of oxygen, therefore hydrogen is the limiting reactant.
10 moles of hydrogen will produce 10 moles of water.
1 mole of a gas has a volume of 22.4 L.
If 10.0 L of hydrogen and 6.0 L of oxygen were used, 10.0 L of water will be produced.
Therefore, the volume ratio of gas equals mole ratio of gas.
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